Algebra

    Solve the compound in" rel="nofollow">inequalities. Be careful of how a negative x-term is handled in" rel="nofollow">in the solvin" rel="nofollow">ing process. Show all math work arrivin" rel="nofollow">ing at the solutions. Show the solution sets written algebraically and as a union or in" rel="nofollow">intersection of in" rel="nofollow">intervals. Describe in" rel="nofollow">in words what the solution sets mean, and then display a simple lin" rel="nofollow">ine graph for each solution set. Incorporate the followin" rel="nofollow">ing five math vocabulary words in" rel="nofollow">into your discussion. Use bold font to emphasize the words in" rel="nofollow">in your writin" rel="nofollow">ing. Do not write defin" rel="nofollow">initions for the words; use them appropriately in" rel="nofollow">in sentences describin" rel="nofollow">ing your math work. Compound in" rel="nofollow">inequalities And Or Intersection Union Problems: ″and″ compound in" rel="nofollow">inequality –2 ˂ –4 + x ≤ 22 ″or″ compound in" rel="nofollow">inequality 5x + 1 ≥ 6 or 2x – 5 ≤ –11     Problem 1. “and" compound in" rel="nofollow">inequality:-2 < -4 + x s 22-2 < -4+x and-4+x s 22x-4> -2 andx s 22+4x > -2+ 4andx s 26Ix > 2 andx s 262 26(2. 26]This is the in" rel="nofollow">intersection of sets.Problem 2, “or" compound in" rel="nofollow">inequality:5x + 1 2 6or 2x- 5 3-1151'325or2xs-11-I-5I've subtracted 1 from each side, and added 5 to each side.5x 2 5 or 2x 3 -6Here. -11+5 was simplified.x 2 1 or x s -3Divided byS. and divided both sides by2.x e [1, to) or x e (-m, -3]x e (-m, -3] U [1, C13)The solution set written in" rel="nofollow">in in" rel="nofollow">interval notation is the union of two in" rel="nofollow">intervals.